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Grade 10 Notes of Linear Programming || Optional Mathematics

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Linear inequalities in two variables are graphed by drawing the boundary line (solid if ≤ or ≥, dotted if < or >) and shading the region where a test point satisfies the inequality, usually using the origin unless it lies on the line. A system of linear inequalities has a feasible region formed by the intersection of all shaded half-planes. In linear programming, the goal is to maximize or minimize a linear objective function subject to linear constraints; the feasible region is always convex, and by the Fundamental Theorem of Linear Programming, the optimal value is attained at one of the vertices (corner points) of the feasible region. To solve graphically, plot all constraints, identify the feasible region, find its vertices by solving the intersections of boundary lines, evaluate the objective function at each vertex, and select the maximum or minimum as required.

1.REVIEW OF LINEAR EQUATIONS AND INEQUALITIES

1.1 Linear Equation in Two Variables

A linear equation in two variables x and y is of the form:

ax + by + c = 0

Where:
1.a, b, c → constants
2.x, y → variables

Represents a straight line in the plane.

1.2 Linear Inequality in Two Variables

A linear inequality in two variables can be of the form:

ax + by + c > 0
ax + by + c < 0
ax + by + c ≥ 0
ax + by + c ≤ 0

Example: x ≥ 3

1.Boundary line: x = 3
2.Region: all points to the right of the line
3.Solid line → ≥ or ≤
4.Dotted line → > or <

 

2.GRAPH OF LINEAR INEQUALITIES

Example 1: 2x + 3y ≥ 6

Boundary line: 2x + 3y = 6

x036
y20-2

1.Draw solid line
2.Test point (0,0): 2(0) + 3(0) ≥ 6 → 0 ≥ 6 → False
3.Shade opposite side of origin

Example 2: 2x − 3y < 6

Boundary line: 2x − 3y = 6

x30-3
y0-2-4

1.Draw dotted line
2.Test point (0,0): 0 − 0 < 6 → True
3.Shade region containing origin

Note: If the boundary passes through origin, test another point (1,0) or (0,1)

How to Solve Linear Inequalities in Two Variables?

3.SYSTEM OF LINEAR INEQUALITIES

A system consists of two or more inequalities with a common solution region.

Example: x − 2y ≥ 4, 2x + y ≤ 8

Boundary Lines and Points:

Linexy
x − 2y = 440
 0-2
2x + y = 808
 40

Common shaded region = Feasible Region

4.LINEAR PROGRAMMING (L.P.)

Definition: A method to maximize or minimize a linear objective function under given constraints.

4.1 Basic Terms

1.Decision Variables → x, y
2.Objective Function → F = 4x − y
3.Constraints → e.g., 2x + 3y ≥ 6
4.Feasible Region → intersection of all constraints
5.Feasible Solution → any point in feasible region
6.Optimal Solution → occurs at vertices of feasible region

Important Rule: Maximum or minimum occurs at vertices only

5.STEPS TO SOLVE L.P. PROBLEMS

1.Identify decision variables and objective function
2.Convert constraints into equations (boundary lines)
3.Draw boundary lines on graph
4.Solid line if ≤ or ≥, Dotted line if < or >
5.Identify feasible region
6.Find vertices of feasible region
7.Evaluate objective function at each vertex
8.Select maximum and minimum value

6.EXAMPLE PROBLEMS

Example 1: Maximize F = 4x − y

Constraints: 2x + 3y ≥ 6, 2x − 3y ≤ 6, y ≤ 2

VertexCoordinatesF = 4x − y
A(3,0)12
B(6,2)22 (Max)
C(0,2)-2 (Min)

Example 2: Max/Min Z = 2x + y

Constraints: x + y ≤ 6, x − y ≤ 4, x ≥ 0, y ≥ 0

VertexCoordinatesZ = 2x + y
O(0,0)0 (Min)
A(4,0)8
B(5,1)11 (Max)
C(0,6)6

Example 3: Minimize Z = 5x + 4y

Constraints: 2x + y ≥ 4, x + 2y ≥ 6, x ≥ 0, y ≥ 0

VertexCoordinatesZ = 5x + 4y
A(2,0)10 (Min)
B(0,3)12
C(4/3,4/3)12

Example 4: Maximize P = 7x + 5y

Constraints: x + y ≤ 10, x ≤ 6, y ≤ 8, x ≥ 0, y ≥ 0

VertexCoordinatesP = 7x + 5y
A(0,0)0
B(6,0)42
C(6,4)62 (Max)
D(2,8)54

 

7. Important Notes

1.Feasible region is always convex
2.Maximum/Minimum occurs only at vertices
3.Always test a point to decide shading
4.Solid line includes boundary, dotted line excludes boundary
5.Check non-negativity constraints (x ≥ 0, y ≥ 0)

 

Visit this link for further practice!!

https://besidedegree.com/exam/s/academic

 

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